JEE Main 2020PhysicsThermal Properties of MatterEasyNumerical

JEE Main 2020 — Thermal Properties of Matter Question with Solution

JEE Main 2020 (07 Jan Shift 2)

Question

M grams of steam at 100oC is mixed with 200g of ice at its melting point in a thermally insulated container. If it produces liquid water at 40oC [heat of vaporization of water is 540cal/g and heat of fusion of ice is 80cal/g ], the value of M is ________

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Show full solutionCorrect answer: 40
Correct answer
40

Step-by-step explanation

MiceLf+Mice40-0Cw=MsteamLv+Msteam100-40Cw
⇒20080+401=M540+601
⇒200120=M600
M=40 gm

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About this question

This is a previous-year question from JEE Main 2020, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.