JEE Main 2023PhysicsThermal Properties of MatterMediumMCQ

JEE Main 2023 — Thermal Properties of Matter Question with Solution

JEE Main 2023 (11 Apr Shift 1)

Question

On a temperature scale 'X', the boiling point of water is 65°X and the freezing point is -15°X. Assuming that the X scale is linear. The equivalent temperature corresponding to -95°X on the Fahrenheit scale would be

Choose an option

Show full solutionCorrect option: C
Correct answer
C-148°F

Step-by-step explanation

The relation between two temperature scales can be written as follows

65-x65--15=212-F180   ...1

Substitute the values of the known parameters in to equation (1) and sole to calculate the required temperature in Fahrenheit scale.

65+9580=212-F180⇒2×180=212-F⇒F=212-360=-148°F

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About this question

This is a previous-year question from JEE Main 2023, covering the Thermal Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.