JEE Main 2020 — Rotational Motion Question with Solution
From: JEE Main 2020 (Online) 2nd September Morning Slot
Question
Shown in the figure is rigid and uniform one meter long rod AB held in horizontal position by two strings tied to its ends and attached to the ceiling. The rod is of mass ‘m’ and has another weight of mass 2 m hung at a distance of 75 cm from A. The tension in the string at A is :
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: D
Correct answer
D1 mg
Step-by-step explanation
B = 0 (torque about point B is zero)
(T A) × 100 – (mg) × 50 – (2mg) × 25 = 0
100T A = 100 mg
TA = 1 mg
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This is a previous-year question from JEE Main 2020, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.