JEE Main 2019 — Rotational Motion Question with Solution
From: JEE Main 2019 (Online) 10th April Evening Slot
Question
The time dependence of the position of a particle of mass m = 2 is given by
. Its angular
momentum, with respect to the origin, at time t = 2 is
Choose an option
Show full solutionCorrect option: B
Correct answer
B- 48
Step-by-step explanation
At t = 2
At t = 2
\overrightarrow L = \overrightarrow r \times \overrightarrow P = \left| {\matrix{ {\widehat i} & {\widehat j} & {\widehat k} \cr 4 & { - 12} & 0 \cr 4 & { - 24} & 0 \cr } } \right|
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This is a previous-year question from JEE Main 2019, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.