JEE Main 2019 — Rotational Motion Question with Solution
From: JEE Main 2019 (Online) 10th April Morning Slot
Question
A particle of mass m is moving along a
trajectory given by
x = x0 + a cos1t
y = y0 + b sin2t
The torque, acting on the particle about the origin, at t = 0 is :
x = x0 + a cos1t
y = y0 + b sin2t
The torque, acting on the particle about the origin, at t = 0 is :
Choose an option
Show full solutionCorrect option: B
Correct answer
B+my0a
Step-by-step explanation
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This is a previous-year question from JEE Main 2019, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.