JEE Main 2020 — Rotational Motion Question with Solution
From: JEE Main 2020 (Online) 7th January Evening Slot
Question
Consider a uniform cubical box of side a on a rough floor that is to be moved by applying
minimum possible force F at a point b above its centre of mass (see figure). If the coefficient of
friction is = 0.4, the maximum possible value of 100 ×
for box not to topple before moving
is .......This question includes a diagram. The text above accompanies the figure.
Enter your answer
Show full solutionCorrect answer: 50
Correct answer
50
Step-by-step explanation
Torque about Center Of Mass
Fb + f = N ...(1)
For not sliding
F = f = N ....(2)
N = Mg ...(3)
N = Mg
4b = 3
b = 0.75
which is not possible as as b can maximum be equal to 0.5
= 0.5
So 100 × = 50
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This is a previous-year question from JEE Main 2020, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.