JEE Main 2021 — Rotational Motion Question with Solution
From: JEE Main 2021 (Online) 24th February Morning Shift
Question
Moment of inertia (M. I.) of four bodies, having same mass and radius, are reported as;
I1 = M.I. of thin circular ring about its diameter,
I2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre,
I3 = M.I. of solid cylinder about its axis and
I4 = M.I. of solid sphere about its diameter.
Then :
I1 = M.I. of thin circular ring about its diameter,
I2 = M.I. of circular disc about an axis perpendicular to disc and going through the centre,
I3 = M.I. of solid cylinder about its axis and
I4 = M.I. of solid sphere about its diameter.
Then :
Choose an option
Show full solutionCorrect option: A
Correct answer
AI1 = I2 = I3 > I4
Step-by-step explanation
Let M and R be the mass and radius of four bodies. Then, as per
question, their moment of inertia are
I1 = ,
I2 = ,
I3 = ,
I4 =
I1 = I2 = I3 > I4
I1 = ,
I2 = ,
I3 = ,
I4 =
I1 = I2 = I3 > I4
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