JEE Main 2015PhysicsRotational MotionMediumMCQ

JEE Main 2015 — Rotational Motion Question with Solution

JEE Main 2015 (10 Apr Online)

Question

A uniform solid cylindrical roller of mass m is being pulled on a horizontal surface with force F parallel to the surface and applied at its centre. If the acceleration of the cylinder is a and it is rolling without slipping then the value of F is:

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Show full solutionCorrect option: A
Correct answer
A32 ma

Step-by-step explanation



From free body diagram of cylinder

F-fs=ma .....(1)

∵   ∑ fext=macm

also ∑τext=Icmα

⟹fs R=Icmα

⟹fs R=12 mR2α ..... (2)

For rolling without slipping



a=Rα ...... (3)

⟹ α=aR

∴   fs R=12mR2aR

⟹ fs=12ma

Put in (1)

F-12ma=ma

⟹F=32ma 

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About this question

This is a previous-year question from JEE Main 2015, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.