JEE Main 2025 — Rotational Motion Question with Solution
JEE Main 2025 (24 Jan Shift 2)
Question
A solid sphere is rolling without slipping on a horizontal plane. The ratio of the linear kinetic energy of the centre of mass of the sphere and rotational kinetic energy is :
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
$\begin{aligned}
& \mathrm{KE}_{(T)}=\frac{1}{2} m v^2 \\
& \mathrm{KE}_{(R)}=\frac{1}{2} \cdot \frac{2}{5} m R^2 \cdot \frac{v^2}{R^2}=\frac{1}{2} m v^2\left(\frac{2}{5}\right)
\end{aligned}$
So,
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This is a previous-year question from JEE Main 2025, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.