JEE Main 2020PhysicsRotational MotionHardMCQ

JEE Main 2020 — Rotational Motion Question with Solution

JEE Main 2020 (08 Jan Shift 2)

Question

A uniform sphere of mass 500 g rolls without slipping on a plane horizontal surface with its centre moving at a speed of 5.00 cm s-1. Its kinetic energy is:

Choose an option

Show full solutionCorrect option: A
Correct answer
A8.75×10-4 J

Step-by-step explanation

K.E of the sphere = Translational K.E+ Rotational K.E
=12mv21+K2R2 ,K= Radius of gyration
= 12×12×210021+25
= 354×10-4 J
= 8.75×10-4 J

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About this question

This is a previous-year question from JEE Main 2020, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.