JEE Main 2017PhysicsRotational MotionHardMCQ

JEE Main 2017Rotational Motion Question with Solution

JEE Main 2017 (09 Apr Online)

Question

A circular hole of radius R4 is made in a thin uniform disc having mass and radius R, as shown in figure. The moment of inertia of the remaining portion of the disc about an axis passing through the point O and perpendicular to the plane of the disc is-

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Show full solutionCorrect option: B
Correct answer
B237MR2512

Step-by-step explanation

ID=mr22

Moment of inertia of removed portion about the axis.

Iremoved=12  m16  r216+m16  9r216   (by parallel axis theorem)

=mr2+18mr2512

=19mr2512

Iremaining=mr22-19512 mr2

=237512 mr2

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About this question

This is a previous-year question from JEE Main 2017, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.