JEE Main 2023PhysicsRotational MotionHardNumerical

JEE Main 2023 — Rotational Motion Question with Solution

JEE Main 2023 (15 Apr Shift 1)

Question

A solid sphere and a solid cylinder of same mass and radius are rolling on a horizontal surface without slipping. The ratio of their radius of gyrations respectively ksph:kcyl is 2:x. The value of x is _______.

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Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Considering rotational axis as the diametrical axis for sphere and axis of cylinder. Then

K12=25R2 and K22=12R2

∴ K1K2=2/51/2=45

⇒K1K2=25

Comparing it with the given value in the question,

25=2x

∴ x=5

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About this question

This is a previous-year question from JEE Main 2023, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.