JEE Main 2014PhysicsRotational MotionHardMCQ

JEE Main 2014 — Rotational Motion Question with Solution

JEE Main 2014 (19 Apr Online)

Question

Consider a cylinder of mass M resting on a rough horizontal rug that is pulled out from under it with acceleration 'a' perpendicular to the axis of the cylinder. What is Ffriction at point P ? It is assumed that the cylinder does not slip.

Choose an option

Show full solutionCorrect option: C
Correct answer
C Ma 3

Step-by-step explanation



For no slipping at P
a 1 + α R = a    →    (1)



f = Ma 1 = M a - α R    →    (2)

f. R = I · α = MR 2 2 · α    →    (3)

Solve the equations (2) and (3)

f = Ma 3 ​

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About this question

This is a previous-year question from JEE Main 2014, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.