JEE Main 2017PhysicsRotational MotionHardMCQ

JEE Main 2017Rotational Motion Question with Solution

JEE Main 2017 (08 Apr Online)

Question

Moment of inertia of an equilateral triangular lamina ABC, about the axis passing through its centre O and perpendicular to its plane is I0 as shown in the figure. A cavity DEF is cut out from the lamina, where D, E, F are the mid points of the sides. Moment of inertia of the remaining part of lamina about the same axis is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B 15 16 I 0

Step-by-step explanation

Given,

AB=BC=AC=l

Moment of inertia of a triangular lamina ABC

I0=kml2

DE=EF=DF=12,

AB=l2

Moment of inertia of DEF

IDEF=km4l22

IDEF=k16 ml2.

IDEF=I016

Moment of inertia of the remaining part

Iremain=I0-I016

=15I016

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About this question

This is a previous-year question from JEE Main 2017, covering the Rotational Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.