JEE Main 2024PhysicsRay OpticsEasyMCQ

JEE Main 2024 — Ray Optics Question with Solution

JEE Main 2024 (29 Jan Shift 2)

Question

If the distance between object and its two times magnified virtual image produced by a curved mirror is 15 cm, the focal length of the mirror must be :

Choose an option

Show full solutionCorrect option: C
Correct answer
C-10 cm

Step-by-step explanation

Let object be at a distance x cm from the pole. Then, distance of image from the pole will be =15-x.

Given:

Magnification, m=2=-vu

⇒2=-(15-x)-x

⇒2x=15-x

⇒3x=15⇒x=5 cm

Now,

Distance of the image from the pole =15-x=15-5=10 cm

Therefore, v=10 cm

From mirror formula:

1f=1v+1u

=110+1(-5)=1-210=-110

⇒f=-10 cm

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About this question

This is a previous-year question from JEE Main 2024, covering the Ray Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.