JEE Main 2016PhysicsRay OpticsMediumMCQ

JEE Main 2016 — Ray Optics Question with Solution

JEE Main 2016 (03 Apr)

Question

In an experiment for determination of refractive index of glass of a prism by i v/s δ plot, it was found that a ray incident at angle 35o , suffers a deviation of 40o and that it emerges at angle 79o . In that case which of the following is closest to the maximum possible value of the refractive index?

Choose an option

Show full solutionCorrect option: C
Correct answer
C1.5

Step-by-step explanation

i=35o, δ=40o, e=79o

δ=i+e-A

40o=35o+79o-A

A=74o

And r1+r2=A=74o

Since δmin<40o

μ<sin⁡74+402sin⁡37

μmax=1.44

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About this question

This is a previous-year question from JEE Main 2016, covering the Ray Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.