JEE Main 2025 — Ray Optics Question with Solution
JEE Main 2025 (29 Jan Shift 2)
Question
Two concave refracting surfaces of equal radii of curvature and refractive index 1.5 face each other in air as shown in figure. A point object O is placed midway, between P and B . The separation between the images of , formed by each refracting surface is :
Choose an option
Show full solutionCorrect option: D
Correct answer
D0.114 R
Step-by-step explanation
For B
$\begin{aligned}
& \frac{\mu_2}{\mathrm{~V}}-\frac{\mu_1}{\mathrm{u}}=\frac{\mu_2-\mu_1}{\mathrm{R}} \\
& \frac{1.5}{\mathrm{~V}}+\frac{1}{\frac{R}{2}}=\frac{0.5}{-\mathrm{R}} \\
& \frac{1.5}{\mathrm{~V}}=-\frac{1}{2 \mathrm{R}}-\frac{2}{\mathrm{R}} \\
& \frac{1.5}{\mathrm{~V}}=\frac{-5}{2 \mathrm{R}} \Rightarrow V_B=-0.6 \mathrm{R}
\end{aligned}$
For A
$\begin{aligned}
& \frac{1.5}{V}+\frac{2}{3 R}=\frac{0.5}{-R} \\
& \frac{1.5}{V}=-\frac{1}{2 R}-\frac{2}{3 R} \\
& \frac{1.5}{V}=-\frac{7}{6 R} \\
& V_A=-\frac{9}{7} R
\end{aligned}$
Distance between images
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This is a previous-year question from JEE Main 2025, covering the Ray Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.