JEE Main 2020PhysicsRay OpticsEasyNumerical

JEE Main 2020Ray Optics Question with Solution

JEE Main 2020 (05 Sep Shift 2)

Question

A prism of angle A=1° μ=1.5. A good estimate for the minimum angle of deviation (in degrees) is close to N10. Value of N is 
 

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Show full solutionCorrect answer: 5
Correct answer
5

Step-by-step explanation

Given,

Angle of prism, A=1°

Refractive index of prism, μ=1.5

For this prism, minimum angle of deviation is given by

δ=(μ-1)A

δ=(1.5-1)×1°=12=510=N10

N=5

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About this question

This is a previous-year question from JEE Main 2020, covering the Ray Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.