JEE Main 2022PhysicsRay OpticsMediumMCQ

JEE Main 2022 — Ray Optics Question with Solution

JEE Main 2022 (27 Jul Shift 1)

Question

A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air is , calculate the change of microscope's resolving power due to oil and choose the correct option

Choose an option

Show full solutionCorrect option: B
Correct answer
BResolving power will be twice in the oil than it was in the air.

Step-by-step explanation

Resolving power of microscope in air is (R.P)air =2μairsinθ1.22λ=2sinθ1.22λ

(R.P)oil =2μoilsinθ1.22λoil =2sinθ21.22λ

R.Poil=R.Pair×2

Thus, resolving power in oil is twice the resolving power in air.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Ray Optics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Ray Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.