JEE Main 2022PhysicsRay OpticsMediumNumerical

JEE Main 2022 — Ray Optics Question with Solution

JEE Main 2022 (28 Jul Shift 2)

Question

An object 'O' is placed at a distance of 100 cm in front of a concave mirror of radius of curvature 200 cm as shown in the figure. The object starts moving towards the mirror at a speed 2 cm s-1. The position of the image from the mirror after 10 s will be at _____ cm.

Enter your answer

Show full solutionCorrect answer: 400
Correct answer
400

Step-by-step explanation

In 10 s, the object will travel distance =2×10=20 cm

After 10 sec, the object will be at distance u=20-100=-80 m.

Focal length of the concave mirror is  f=R2=2002=-100 cm

Using mirror formula,

1v+1u=1f

⇒1v=-1100+180⇒v=800020

⇒v=400 cm

Position of image from the mirror is at 400 cm.

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Ray Optics chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Ray Optics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.