JEE Main 2023PhysicsNuclear PhysicsHardMCQ

JEE Main 2023Nuclear Physics Question with Solution

JEE Main 2023 (08 Apr Shift 1)

Question

For a nucleus XZA having mass number A and atomic number Z

A. The surface energy per nucleon (bs)=a1A23.

B. The Coulomb contribution to the binding energy bc=a2Z(Z1)A43.

C. The volume energy bv = a3A

D. Decrease in the binding energy is proportional to surface area.

E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons. (a1, a2 and a3 are constants)

Choose the most appropriate answer from the options given below:

Choose an option

Show full solutionCorrect option: B
Correct answer
BC, D only

Step-by-step explanation

The formula to calculate the radius of a nucleus is given by

R=R0A13   ...1

Hence, the volume energy can be written as

bv=C1R3= a3A133=a3A

The nuclear binding energy is the minimum energy that is required to disassemble the nucleus of an atom into its constituent protons and neutrons. Also, the energy of the nucleus is negative with regard to the energy of the particles pulled apart to infinite distance, because energy must be utilised to split a nucleus into its individual protons and neutrons. It is proportional to the surface area.

Hence, statements C and D are most appropriate.

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About this question

This is a previous-year question from JEE Main 2023, covering the Nuclear Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.