JEE Main 2022PhysicsNuclear PhysicsEasyMCQ

JEE Main 2022 — Nuclear Physics Question with Solution

JEE Main 2022 (26 Jul Shift 1)

Question

The disintegration rate of a certain radioactive sample at any instant is 4250 disintegrations per minute. 10 minutes later, the rate becomes 2250 disintegrations per minute. The approximate decay constant is

(Take loge1.88=0.63)

Choose an option

Show full solutionCorrect option: C
Correct answer
C0.063 min-1

Step-by-step explanation

At t=0 disintegration rate A0=4250 dpm

At t=10 min disintegration rate At=2250dpm

The activity of a sample at any time is given by,

At=A0e-λt

⇒2250=4250e-λ10

⇒10λ=ln42502250=ln1.88

⇒λ=0.063 min-1

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About this question

This is a previous-year question from JEE Main 2022, covering the Nuclear Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.