JEE Main 2019PhysicsNuclear PhysicsMediumMCQ

JEE Main 2019Nuclear Physics Question with Solution

JEE Main 2019 (12 Jan Shift 2)

Question

In a radioactive decay chain, the initial nucleus is  90232Th. At the end, there are 6 α-particles and 4β-particles which are emitted. If the end nucleus is ZAX, A and Z are given by:

Choose an option

Show full solutionCorrect option: A
Correct answer
AA=208;Z=82

Step-by-step explanation

As we know that in alpha decay mass number reduced from for and the atomic number reduced by two

and in beta decay the mass number became unchange and atomic number increase from one

Change in Z=6×2-4=8
Change in A=6×4-4=8
TH902326α4β PB82208

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About this question

This is a previous-year question from JEE Main 2019, covering the Nuclear Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.