JEE Main 2024PhysicsMotion In Two DimensionsEasyMCQ

JEE Main 2024 — Motion In Two Dimensions Question with Solution

JEE Main 2024 (29 Jan Shift 1)

Question

If the radius of curvature of the path of two particles of same mass are in the ratio 3: 4, then in order to have constant centripetal force, their velocities will be in the ratio of:

Choose an option

Show full solutionCorrect option: A
Correct answer
A3:2

Step-by-step explanation

Given m1=m2 and r1r2=34

As centripetal force is given by F=mv2r, in order to have the same centripetal force, we can write

F1=F2⇒m1v12r1=m2v22r2⇒v1v2=r1r2=32

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About this question

This is a previous-year question from JEE Main 2024, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.