JEE Main 2014PhysicsMotion In Two DimensionsMediumMCQ

JEE Main 2014 — Motion In Two Dimensions Question with Solution

JEE Main 2014 (09 Apr Online)

Question

The position of a projectile launched from the origin at t = 0 is given by r → = 4 0  i⁡ ^ + 5 0  j⁡ ^ m   at t = 2s. If the projectile was launched at an angle θ  from the horizontal, then θ   is (take g = 10 ms-2).

Choose an option

Show full solutionCorrect option: C
Correct answer
C tan - 1 7 4

Step-by-step explanation

From question, Horizontal velocity (initial),
ux=402=20 m/s
Vertical velocity (initial), 50=uyt+12gt2

⇒50= uy×2+12(-10)×4
     50=2uy-20
      uy=702=35 m/s
∴  tanθ=uyux=3520=74
⇒  θ=tan-174

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About this question

This is a previous-year question from JEE Main 2014, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.