JEE Main 2024PhysicsMotion In Two DimensionsHardMCQ

JEE Main 2024 — Motion In Two Dimensions Question with Solution

JEE Main 2024 (01 Feb Shift 1)

Question

A particle moving in a circle of radius R with uniform speed takes time T to complete one revolution. If this particle is projected with the same speed at an angle θ to the horizontal, the maximum height attained by it is equal to 4R. The angle of projection θ is then given by :

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Show full solutionCorrect option: A
Correct answer
Asin−12gT2π2R12

Step-by-step explanation

Time period of circular motion is given by, 

2πRv=T⇒v=2πRT

Now, maximum height H=v2sin2θ2g

⇒4R=4π2R2T2sin2θ2g

⇒sinθ=2gT2π2R

⇒θ=sin−12gT2π2R12

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About this question

This is a previous-year question from JEE Main 2024, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.