JEE Main 2020PhysicsMotion In Two DimensionsEasyMCQ

JEE Main 2020 — Motion In Two Dimensions Question with Solution

JEE Main 2020 (09 Jan Shift 2)

Question

A particle starts from the origin at t=0 with an initial velocity of 3.0i^m/s and moves in the x-y plane with a constant acceleration 6.0i^+4.0j^m/s2. The x- coordinate of the particle at the instant when its y- coordinate is 32m is D meters. The value of D is:

Choose an option

Show full solutionCorrect option: C
Correct answer
C60

Step-by-step explanation

Sy=uyt+12ayt2
32=0+12×4t2⇒t=4 s
Sx=uxt+12axt2
=3×4+12×6×16
=60 m 

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About this question

This is a previous-year question from JEE Main 2020, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.