JEE Main 2022PhysicsMotion In Two DimensionsEasyMCQ

JEE Main 2022 — Motion In Two Dimensions Question with Solution

JEE Main 2022 (25 Jul Shift 2)

Question

A ball is projected from the ground with a speed 15 m s-1 at an angle θ with horizontal so that its range and maximum height are equal, then tanθ will be equal to

Choose an option

Show full solutionCorrect option: D
Correct answer
D4

Step-by-step explanation

The range and the maximum height of the projectile are given as below,

R=u2sin2θg=2u2sinθcosθgH=u2sin2θ2g

Therefore,

As H=R

⇒tanθ=4

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About this question

This is a previous-year question from JEE Main 2022, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.