JEE Main 2022PhysicsMotion In Two DimensionsMediumMCQ

JEE Main 2022Motion In Two Dimensions Question with Solution

JEE Main 2022 (25 Jun Shift 2)

Question

Given below are two statements. One is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Two identical balls A and B thrown with same velocity 'u' at two different angles with horizontal attained the same range R. If A and B reached the maximum height h1 and h2 respectively, then R=4h1h2

Reason R: Product of said heights. h1h2=u2sin2θ2g·u2cos2θ2g

Choose an option

Show full solutionCorrect option: A
Correct answer
ABoth A and R are true and R is the correct explanation of A.

Step-by-step explanation

Range of two balls are R1=u2sin2θ1g=R2=u2sin2θ2g.

Now, maximum height by both balls are h1=u2sin2θ12g andh2=u2cos2θ22g

h1h2=u2sin2θ2gu2cos2θ2g=u2sinθcosθ2g=R4

R=4h1h2

Hence, both A and R are true and R is the correct explanation of A.

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About this question

This is a previous-year question from JEE Main 2022, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.