JEE Main 2019PhysicsMotion In Two DimensionsHardMCQ

JEE Main 2019 — Motion In Two Dimensions Question with Solution

JEE Main 2019 (10 Apr Shift 2)

Question

A plane is inclined at an angle α=30° with respect to the horizontal. A particle is projected with a speed  u=2 m s-1 , from the base of the plane, making an angle θ=15° with respect to the plane as shown in the figure. The distance from the base, at which the particle hits the plane is close to:
(Take  g=10 m s-2 )

Choose an option

Show full solutionCorrect option: A
Correct answer
A20 cm

Step-by-step explanation

Range =2u2sinαcos⁡α+θgcos2⁡θ
α=angle of inclination=30°
θ=angle of projection from inclination=15°
u=2 m/s
R=222sin15°cos⁡15°+30°gcos2⁡30°=8sin⁡15°cos45°g cos230°  sin15°=3-122
R=453-1 3≈0.2 m
R≈20 cm

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About this question

This is a previous-year question from JEE Main 2019, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.