JEE Main 2023PhysicsMotion In Two DimensionsEasyMCQ

JEE Main 2023 — Motion In Two Dimensions Question with Solution

JEE Main 2023 (10 Apr Shift 1)

Question

The range of the projectile projected at an angle of 15∘ with horizontal is 50 m. If the projectile is projected with same velocity at an angle of 45∘ with horizontal, then its range will be

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Show full solutionCorrect option: A
Correct answer
A100 m

Step-by-step explanation

The data given is 

θ1=15°θ2=45°R1=50 m

The formula for range of a projectile is given by 

R=u2 sin2θg   ...(i)

Substituting the values in equation (i)

R1=u2sin2θ1g⇒50=u2sin30°g⇒u2g=100

Let the new range be R2. The magnitude of the range is 

R2=u2sin2θ2g⇒R2=u2gsin90°⇒R2=100 m

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About this question

This is a previous-year question from JEE Main 2023, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.