JEE Main 2022PhysicsMotion In Two DimensionsEasyMCQ

JEE Main 2022 — Motion In Two Dimensions Question with Solution

JEE Main 2022 (29 Jun Shift 2)

Question

A person can throw a ball upto a maximum range of 100 m. How high above the ground he can throw the same ball?

Choose an option

Show full solutionCorrect option: B
Correct answer
B50 m

Step-by-step explanation

Horizontal range is maximum if the angle of projection is 45° and is given by Rmax=u2g

Here, Rmax=100 m

Then, 100=u2g  ⋯1

If the ball is thrown vertically upward, then the ball will attain the maximum height from the ground as Hmax=u22g

Hmax=1002=50 m

Practice this on the real CBT interface

Solve this JEE Main question (and the rest of the Motion In Two Dimensions chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.

Solve interactively →

About this question

This is a previous-year question from JEE Main 2022, covering the Motion In Two Dimensions chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.