JEE Main 2022PhysicsMagnetic Properties of MatterEasyMCQ

JEE Main 2022 — Magnetic Properties of Matter Question with Solution

JEE Main 2022 (25 Jul Shift 2)

Question

An electron with energy 0.1keV moves at right angle to the earth's magnetic field of 1×10-4Wbm-2. The frequency of revolution of the electron will be
(Take mass of electron =9.0×10-31 kg)

Choose an option

Show full solutionCorrect option: C
Correct answer
C2.8×106 Hz

Step-by-step explanation

The frequency of revolution of the electron is f=eB2πm, here, e is charge of electron, B is magnetic field and m is mass of electron.

So, f=1.6×10-19×10-42π×9×10-31=2.8×106 Hz

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About this question

This is a previous-year question from JEE Main 2022, covering the Magnetic Properties of Matter chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.