JEE Main 2017PhysicsMagnetic Effects of CurrentMediumMCQ

JEE Main 2017Magnetic Effects of Current Question with Solution

JEE Main 2017 (08 Apr Online)

Question

In a certain region static electric and magnetic fields exist. The magnetic field is given by B=B0i^+2j^-4k^. If a test charge moving with a velocity v=v03i^-j^+2k^ experiences no force in that region, then the electric field in the region, in SI units, is:

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Show full solutionCorrect option: D
Correct answer
DE=-v0 B014j^+7k^

Step-by-step explanation

The total force experienced by test charge is Fe+ Fm=0.

Fe=-Fm

Fe=q0v0B0V×B

Fe=-q0 v0B03i^- j^+2k^×i^+2j^-4k^

Fe= -qv0B0 (14j^ +7k^)

The electric field produced by the test charge is    E= feq= -v0B0 ( 14j^+7k^)

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About this question

This is a previous-year question from JEE Main 2017, covering the Magnetic Effects of Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.