JEE Main 2012 — Magnetic Effects of Current Question with Solution
JEE Main 2012 (19 May Online)
Question
A proton and a deuteron are both accelerated through the same potential difference and enter in a magnetic field perpendicular to the direction of the field. If the deuteron follows a path of radius , assuming the neutron and proton masses are nearly equal, the radius of the proton's path will be
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
As charge on both proton and deuteron is same i.e. ' '
Energy acquired by both, For Deuteron.
Kinetic energy,
[ is the potential difference]
But
Therefore,
Radius of path,
Substituting value of ' ' we get
For proton :
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This is a previous-year question from JEE Main 2012, covering the Magnetic Effects of Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.