JEE Main 2015PhysicsMagnetic Effects of CurrentMediumMCQ

JEE Main 2015Magnetic Effects of Current Question with Solution

JEE Main 2015 (11 Apr Online)

Question

Two long straight parallel wires, carrying (adjustable) currents I1 and I2 , are kept at a distance d apart. If the force F between the two wires is taken as 'positive' when the wires repel each other and 'negative' when the wires attract each other, the graph showing the dependence of F, on the product I1I2 , would be:

Choose an option

Show full solutionCorrect option: D
Correct answer
D

Step-by-step explanation

Force between two parallel current carrying wires is given as

f=μ0I1I22πdl

FI1I2

When I1, I2 are in same direction the I1I2 is+ve ⇒ attraction ⇒ -ve

When I1I2 are in opposite direction then

I1I2=-ve

Force = repulsive = +ve

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About this question

This is a previous-year question from JEE Main 2015, covering the Magnetic Effects of Current chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.