JEE Main 2021 — Laws Of Motion Question with Solution
From: JEE Main 2021 (Online) 24th February Morning Shift
Question
The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be _________ N. [g = 10 ms2]
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Show full solutionCorrect answer: 25
Correct answer
25
Step-by-step explanation
Given, coefficient of static friction, s = 0.2
Various forces acting on block are shown below
Frictional force mg
N 0.2 5
N 25
Magnitude of horizontal force, F = N = 25 N
Various forces acting on block are shown below
Frictional force mg
N 0.2 5
N 25
Magnitude of horizontal force, F = N = 25 N
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