JEE Main 2012 — Laws of Motion Question with Solution
JEE Main 2012 (19 May Online)
Question
A block of weight rests on a horizontal floor with coefficient of static friction . It is desired to make the block move by applying minimum amount of force. The angle from the horizontal at which the force should be applied and magnitude of the force are respectively.
Choose an option
Show full solutionCorrect option: A
Correct answer
A
Step-by-step explanation
Let the force is applied at an angle with the horizontal.
For horizontal equilibrium, For vertical equilibrium, or, Substituting this value of in eq. (i), we get For to be minimum, the denominator should be maximum. or, or, or, Then, and Hence,
For horizontal equilibrium, For vertical equilibrium, or, Substituting this value of in eq. (i), we get For to be minimum, the denominator should be maximum. or, or, or, Then, and Hence,
Practice this on the real CBT interface
Solve this JEE Main question (and the rest of the Laws of Motion chapter) on PrepSharp's TCS iON-style CBT player — with timer, bookmarks and session analytics.
Solve interactively →About this question
This is a previous-year question from JEE Main 2012, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.