JEE Main 2021 — Laws Of Motion Question with Solution
From: JEE Main 2021 (Online) 16th March Morning Shift
Question
A block of mass m slides along a floor while a force of magnitude F is applied to it at an angle as shown in figure. The coefficient of kinetic friction is k. then, the block's acceleration 'a' is given by :
(g is acceleration due to gravity)
(g is acceleration due to gravity)
This question includes a diagram. The text above accompanies the figure.
Choose an option
Show full solutionCorrect option: B
Correct answer
B
Step-by-step explanation
Drawing the FBD of the block.
N = mg Fsin ..... (1)
Also, Fcos kN = m . a ..... (2)
Substituting the value of N from eq. (1) in eq. (2)
Fcos k(mg Fsin) = m . a
a = cos k
N = mg Fsin ..... (1)
Also, Fcos kN = m . a ..... (2)
Substituting the value of N from eq. (1) in eq. (2)
Fcos k(mg Fsin) = m . a
a = cos k
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This is a previous-year question from JEE Main 2021, covering the Laws Of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.