JEE Main 2023PhysicsLaws of MotionEasyMCQ

JEE Main 2023 — Laws of Motion Question with Solution

JEE Main 2023 (31 Jan Shift 2)

Question

A body of mass 10 kg is moving with an initial speed of 20 m s-1. The body stops after 5 s due to friction between body and the floor. The value of the coefficient of friction is: (Take acceleration due to gravity g=10 m s-2)

Choose an option

Show full solutionCorrect option: D
Correct answer
D0.4

Step-by-step explanation

Friction force wil act opposite to the motion of the body.

F=μN=μmg

⇒a=-μg-ve sign for direction relative to the motion of body

Now, applying equation of motion, we get

v=u+at

⇒0=20+-μ×10×5

⇒50μ=20

 ⇒μ=0.4

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About this question

This is a previous-year question from JEE Main 2023, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.