JEE Main 2017PhysicsLaws of MotionMediumMCQ

JEE Main 2017 — Laws of Motion Question with Solution

JEE Main 2017 (09 Apr Online)

Question

A conical pendulum of length l makes an angle θ=45° with respect to Z-axis and moves in a circle in the XY plane. The radius of the circle is 0.4 m and its center is vertically below O. The speed of the pendulum, in its circular path, will be - Take g=10 m s-2

Choose an option

Show full solutionCorrect option: C
Correct answer
C2 m s-1

Step-by-step explanation


Tsin⁡θ=mv2r

Tcos⁡θ=mg

tan⁡θ=v2rg

θ=45o

v2=rg

v=rg=0.4×10

v=2 m s-1
 

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About this question

This is a previous-year question from JEE Main 2017, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.