JEE Main 2023PhysicsLaws of MotionEasyMCQ

JEE Main 2023 — Laws of Motion Question with Solution

JEE Main 2023 (11 Apr Shift 2)

Question

A body of mass 500 g moves along x-axis such that it's velocity varies with displacement x according to the relation v=10x m s-1 the force acting on the body is:

Choose an option

Show full solutionCorrect option: B
Correct answer
B25 N

Step-by-step explanation

It is given that 

 v=10x m s-1

Force is defined by F=mdvdt   ...(i)

Multiplying and dividing equation (i) by dx

F=mdvdtdxdx⇒F=mdxdtdvdx=mvdvdx   ...(ii)

Finding the values of the terms in equation (ii)
dvdx=102x=5x
vdvdx=a=10x×5x=50 m s-2

Hence, the force is 
F=12×50=25 N.

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About this question

This is a previous-year question from JEE Main 2023, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.