JEE Main 2014 — Laws of Motion Question with Solution
JEE Main 2014 (09 Apr Online)
Question
A block A of mass 4 kg is placed on another block B of mass 5 kg, and the block B rests on a smooth horizontal table. If the minimum force that can be applied on A so that both the blocks move together is 12 N, the maximum force that can be applied on B for the blocks to move together will be :
Choose an option
Show full solutionCorrect option: A
Correct answer
A0 N
Step-by-step explanation
There is an error in this question. Given a smooth horizontal table, there would be no friction between the table and the lower (5 kg) block. As a result the "minimum" force on the upper (4kg) block for both blocks to move together would be 0 N.
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This is a previous-year question from JEE Main 2014, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.