JEE Main 2021PhysicsLaws of MotionHardMCQ

JEE Main 2021Laws of Motion Question with Solution

JEE Main 2021 (16 Mar Shift 2)

Question

Statement I: A cyclist is moving on an unbanked road with a speed of 7 km h-1 and takes a sharp circular turn along a path of the radius of 2 m without reducing the speed. The static friction coefficient is 0.2. The cyclist will not slip and pass the curve g=9.8 m s-2

Statement II : If the road is banked at an angle of 45°, cyclist can cross the curve of 2 m radius with the speed of 18.5 km h-1 without slipping. In the light of the above statements, choose the correct answer from the options given below.

Choose an option

Show full solutionCorrect option: D
Correct answer
DBoth statement I and statement II are true

Step-by-step explanation

Statement Ivmax=μRg=0.2×2×9.8

vmax=1.97 m s-1

7 km h-1=1.944 m s-1

Speed is lower than vmax, hence it can take safe
turn.

Statement II 

vmax=Rgtanθ+μ1-μtanθ

=2×9.81+0.21-0.2=5.42 m s-1

18.5 km h-1=5.14 m s-1

Speed is lower than vmax, hence it can take safe turn.

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About this question

This is a previous-year question from JEE Main 2021, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.