JEE Main 2024PhysicsLaws of MotionMediumMCQ

JEE Main 2024 — Laws of Motion Question with Solution

JEE Main 2024 (27 Jan Shift 1)

Question

A train is moving with a speed of 12 m s-1 on rails which are 1.5 m apart. To negotiate a curve radius 400 m, the height by which the outer rail should be raised with respect to the inner rail is (Given, g= 10 m s-2):

Choose an option

Show full solutionCorrect option: B
Correct answer
B5.4 cm

Step-by-step explanation

For the train, moving along the curved rails, it can be written, with reference to the figure below, that

tanθ=v2Rg   ...1

Also, from the above figure, it follows that

tanθ=h1.5   ...2

Equations (1) and (2) imply that

h1.5=v2Rg⇒h=1.5×v2Rg=1.5×12 m s-12400 m×10 m s-2=0.054 m=5.4 cm

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About this question

This is a previous-year question from JEE Main 2024, covering the Laws of Motion chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.