JEE Main 2019PhysicsGravitationMediumMCQ

JEE Main 2019Gravitation Question with Solution

JEE Main 2019 (10 Jan Shift 1)

Question

A satellite is moving with a constant speed v in circular orbit around the earth. An object of mass 'm' is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of ejection, the kinetic energy of the object is:

Choose an option

Show full solutionCorrect option: B
Correct answer
Bm v2

Step-by-step explanation

At height r from the centre of the Earth, orbital velocity is given as:

orbital velocity = GMr

Ve=2v

K.E=12m2v2=mv2

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About this question

This is a previous-year question from JEE Main 2019, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.