JEE Main 2022PhysicsGravitationEasyMCQ

JEE Main 2022 — Gravitation Question with Solution

JEE Main 2022 (28 Jul Shift 2)

Question

Assume there are two identical simple pendulum Clocks-1 is placed on the earth and Clock-2 is placed on a space station located at a height h above the earth surface. Clock-1 and Clock-2 operate at time periods 4 s and 6 s respectively. Then the value of h is -
(consider radius of earth RE=6400 km and g on earth 10 m s-2)

Choose an option

Show full solutionCorrect option: C
Correct answer
C3200 km

Step-by-step explanation

The time period of a simple pendulum is given by, T=2πlg.

Therefore, T∝1g.

The acceleration due to gravity at height h from the surface of the earth is given by, g'=gR+h2

Therefore,

T1T2=g2g1⇒46=RR+h⇒h=R2=3200 km

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About this question

This is a previous-year question from JEE Main 2022, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.