JEE Main 2024PhysicsGravitationEasyMCQ

JEE Main 2024Gravitation Question with Solution

JEE Main 2024 (04 Apr Shift 1)

Question

A metal wire of uniform mass density having length and mass is bent to form a semicircular arc and a particle of mass is placed at the centre of the arc. The gravitational force on the particle by the wire is :

Choose an option

Show full solutionCorrect option: D
Correct answer
D

Step-by-step explanation


We have $\begin{aligned} & \mathrm{g}_0=\frac{2 \mathrm{G} \frac{\mathrm{M}}{\mathrm{L}}}{\mathrm{R}}=\frac{2 \mathrm{GM} \pi}{\mathrm{L}^2} \\ & \therefore \mathrm{F}_{\mathrm{m}}=\mathrm{mg}_0=\frac{2 \mathrm{GM} \pi \mathrm{m}}{\mathrm{L}^2} \end{aligned}$
Hence option (4)

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About this question

This is a previous-year question from JEE Main 2024, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.