JEE Main 2020PhysicsGravitationMediumMCQ

JEE Main 2020Gravitation Question with Solution

JEE Main 2020 (04 Sep Shift 1)

Question

On the x-axis and at a distance x from the origin, the gravitational field due to a mass distribution is given by Axx2+a23/2 in the x-direction. The magnitude of the gravitational potential on the x-axis at a distance x, taking its value to be zero at infinity is:

Choose an option

Show full solutionCorrect option: A
Correct answer
AAx2+a21/2

Step-by-step explanation

Vx=xAxA2+x23/2dx

Vx=-AA2+x2

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About this question

This is a previous-year question from JEE Main 2020, covering the Gravitation chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.