JEE Main 2026 — Experimental Physics Question with Solution
JEE Main 2026 (23 January Shift 1)
Question
In a screw gauge, the zero of the circular scale lies 3 divisions above the horizontal pitch line when their metallic studs are brought in contact. Using this instrument thickness of a sheet is measured. If pitch scale reading is 1 mm and the circular scale reading is 51 then the correct thickness of the sheet is mm.
[Assume least count is 0.01 mm ]
[Assume least count is 0.01 mm ]
Choose an option
Show full solutionCorrect option: C
Correct answer
C
Step-by-step explanation
For a screw gauge, the measurement formula is: Reading = Pitch scale + (Circular scale × Least count) - Zero error
The zero of circular scale lies 3 divisions above the pitch line, indicating negative zero error:
Zero error = -3 × 0.01 = -0.03 mm
Reading = 1 + (51 × 0.01) - (-0.03) = 1 + 0.51 + 0.03 = 1.54 mm
The zero of circular scale lies 3 divisions above the pitch line, indicating negative zero error:
Zero error = -3 × 0.01 = -0.03 mm
Reading = 1 + (51 × 0.01) - (-0.03) = 1 + 0.51 + 0.03 = 1.54 mm
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This is a previous-year question from JEE Main 2026, covering the Experimental Physics chapter of Physics. PrepSharp catalogues every PYQ from JEE Main with a verified answer key and step-by-step solution prepared by IIT alumni — so you can search by chapter, topic or year and revise efficiently.